NPTEL Basic Electrical Circuits Week 9 Assignment Answers 2024
1.
In the figure shown above, how much time will it take for the capacitor to charge 99.3% of its final value. (Compare it with time constant, for practical purposes we will consider as fully charged)
- 0.210 s
- 0.105 s
- 10.5 ms
- 21 ms
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Based on the above diagram, answer the following Questions.
2. What is the charge across 3 Ī¼F capacitor, just after time t=0
- 7.5 V
- 6.5 V
- 3.5 V
- 10.5 V
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3. What is equation for voltage across 5 Ī¼F capacitor at any time t
- 7.5 – 4. 5e-t/0.048
- 4.5e-t/0.048
- 7.5 – 4. 5e-t/0.01125
- 4. 5e-t/0.1125
Answer :-
4. In the circuit given below, the switch was at position-A for a long time. At t = 0 sec, it is moved to position-B. Find the voltage across the capacitor at t = 1 sec.
- 15 V
- 20.9 V
- 30 V
- -15 V
Answer :-
55. Find i(t) in the circuit shown below for t > 0. Assume that the switch has been closed for a long time before opening. (Multiple Options may be correct)
- i(t) = 5 A, for t ā¤ 0 sec.
- i(t) = 3.1 A, for t = 0.067 sec
- i(t) = 2.5 A, for t = 0.2 sec
- š = 1/15 sec -1 where š is the time constant of the circuit.
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6. In the circuit shown below, the switch was at position A for a long time. At time t = 0 sec, the switch is moved to position B. Find the value of V2 (t) –
Answer :-
7. What will be the charge stored in the capacitor 2Ī¼ F, in the steady state for the below circuit. (Initially both are uncharged)
- 20 Ī¼C
- 6 Ī¼C
- 8 Ī¼C
- 10 Ī¼C
Answer :-
8. In the below circuit, what will be the steady state voltage š0 , and what happens to the steady state voltage, if the capacitance parallel to the 3šā¦ resistor is doubled?
- š0 = 2V, no change in V0
- š0 = 3V, V0 reduces to V0/2
- š0 = 2V, š0 is doubled
- š0 = 3V, no change in V0
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9. What will be the order of the below circuit?
- 1
- 2
- Cannot be determined
- None of the above
Answer :-
10. In the initially relaxed RC circuit shown below,the switch is closed onto position S1 at time t = 0.After time equals one time constant of the RC circuit,the switch is moved to position S2 .Find the capacitor voltages from the options given below.
Answer :-
11. The switch in the circuit shown below was in an open position for a long time. It is closed at time t = 0. Find i l(t) for time t > 0.
- 6e-2t V
- 6e-10t V
- 12(1 – e-2t) V
- 12(1 – e-4t) V
Answer :-
12. Determine the value of voltage Vc at time t = 0.5m sec .Answer the question based on the figure given below.
- 10.3 V
- 12.5 V
- 9.21 V
- 23.5 V
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